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3x^2-44x+140=0
a = 3; b = -44; c = +140;
Δ = b2-4ac
Δ = -442-4·3·140
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-16}{2*3}=\frac{28}{6} =4+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+16}{2*3}=\frac{60}{6} =10 $
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