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3x^2-46x+91=0
a = 3; b = -46; c = +91;
Δ = b2-4ac
Δ = -462-4·3·91
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-32}{2*3}=\frac{14}{6} =2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+32}{2*3}=\frac{78}{6} =13 $
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