3x2-4=1/5(y-5)

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Solution for 3x2-4=1/5(y-5) equation: 


x in (-oo:+oo)

3*x^2-4 = (1/5)*(y-5) // - (1/5)*(y-5)

3*x^2-((1/5)*(y-5))-4 = 0

(-1/5)*(y-5)+3*x^2-4 = 0

3*x^2-1/5*(y-5)-4 = 0

3*x^2-1/5*(y-5)-4 = 0

3*x^2-1/5*y-4+1 = 0

3*x^2-1/5*y-3 = 0

3*x^2-1/5*y-3 = 0

3*x^2 = -(-1/5*y-3) // : 3

x^2 = (3-(-1/5*y))/3

x^2 = (1/5*y+3)/3 // ^ 1/2

abs(x) = ((1/5*y+3)^(1/2))/(3^(1/2))

x = ((1/5*y+3)^(1/2))/(3^(1/2)) or x = -(((1/5*y+3)^(1/2))/(3^(1/2)))

x in { ((1/5*y+3)^(1/2))/(3^(1/2)), -(((1/5*y+3)^(1/2))/(3^(1/2))) }

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