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3x^2-4x-207=0
a = 3; b = -4; c = -207;
Δ = b2-4ac
Δ = -42-4·3·(-207)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-50}{2*3}=\frac{-46}{6} =-7+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+50}{2*3}=\frac{54}{6} =9 $
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