If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2-5x=14-4x
We move all terms to the left:
3x^2-5x-(14-4x)=0
We add all the numbers together, and all the variables
3x^2-5x-(-4x+14)=0
We get rid of parentheses
3x^2-5x+4x-14=0
We add all the numbers together, and all the variables
3x^2-1x-14=0
a = 3; b = -1; c = -14;
Δ = b2-4ac
Δ = -12-4·3·(-14)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-13}{2*3}=\frac{-12}{6} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+13}{2*3}=\frac{14}{6} =2+1/3 $
| 2y^2+5y−1=0 | | 1+b=-18-9 | | -6-3j=-5j | | 2y2+5y−1=0 | | (12x-8)/4=122 | | 0.5x-7=0.5 | | O=-45+x | | (3x)(4x)=(3x+7)(5x-8) | | 5(c-4)+4=3+c-19 | | x(x+1)=702 | | 19=3=4y | | 6x2=x2+5x | | 6x+3(3x-20)=-165 | | 10d+2d=15 | | 12j-j+2j-13j+j=11 | | 5(4x-7)(3x-8)=0 | | -5(2p+4)-36=2(5p+2) | | 27+9x=12 | | 4g-4g+2g-g=8 | | 8y+3y=20 | | 14x-34+9x+1=180 | | 8=3y=20 | | 4a+4a+a-6a-a=14 | | 5z+5z-5z=20 | | 2x(x-8)(5x+9)=0 | | 1000=20x+400 | | I3x-10=26 | | -y^2+2y-1=0 | | 5(x-4)=130 | | 10z-9z=13 | | -40+27y+9=6(5y-2)-4 | | 14t=154 |