3x2-88x+24=0

Solution for 3x2-88x+24=0 equation:

3x^2-88x+24=0

a = 3; b = -88; c = +24;
Δ = b2-4ac
Δ = -882-4·3·24
Δ = 7456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7456}=\sqrt{16*466}=\sqrt{16}*\sqrt{466}=4\sqrt{466}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-88)-4\sqrt{466}}{2*3}=\frac{88-4\sqrt{466}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-88)+4\sqrt{466}}{2*3}=\frac{88+4\sqrt{466}}{6}
$