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3x^2-8x+11=4(x-1)
We move all terms to the left:
3x^2-8x+11-(4(x-1))=0
We calculate terms in parentheses: -(4(x-1)), so:We get rid of parentheses
4(x-1)
We multiply parentheses
4x-4
Back to the equation:
-(4x-4)
3x^2-8x-4x+4+11=0
We add all the numbers together, and all the variables
3x^2-12x+15=0
a = 3; b = -12; c = +15;
Δ = b2-4ac
Δ = -122-4·3·15
Δ = -36
Delta is less than zero, so there is no solution for the equation
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