3x2-x(3x-4)=16+2x

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Solution for 3x2-x(3x-4)=16+2x equation: 



3x^2-x(3x-4)=16+2x

We move all terms to the left:

3x^2-x(3x-4)-(16+2x)=0

We add all the numbers together, and all the variables

3x^2-x(3x-4)-(2x+16)=0

We multiply parentheses

3x^2-3x^2+4x-(2x+16)=0

We get rid of parentheses

3x^2-3x^2+4x-2x-16=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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