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3x^2-x-2=2x^2-x-2
We move all terms to the left:
3x^2-x-2-(2x^2-x-2)=0
We add all the numbers together, and all the variables
3x^2-1x-(2x^2-x-2)-2=0
We get rid of parentheses
3x^2-2x^2-1x+x+2-2=0
We add all the numbers together, and all the variables
x^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{2}=0$
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