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3x^2-x=102
We move all terms to the left:
3x^2-x-(102)=0
We add all the numbers together, and all the variables
3x^2-1x-102=0
a = 3; b = -1; c = -102;
Δ = b2-4ac
Δ = -12-4·3·(-102)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-35}{2*3}=\frac{-34}{6} =-5+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+35}{2*3}=\frac{36}{6} =6 $
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