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3x^2-x=2x+1
We move all terms to the left:
3x^2-x-(2x+1)=0
We add all the numbers together, and all the variables
3x^2-1x-(2x+1)=0
We get rid of parentheses
3x^2-1x-2x-1=0
We add all the numbers together, and all the variables
3x^2-3x-1=0
a = 3; b = -3; c = -1;
Δ = b2-4ac
Δ = -32-4·3·(-1)
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{21}}{2*3}=\frac{3-\sqrt{21}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{21}}{2*3}=\frac{3+\sqrt{21}}{6} $
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