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3x^2/55=2x-45+3x+32
We move all terms to the left:
3x^2/55-(2x-45+3x+32)=0
We add all the numbers together, and all the variables
3x^2/55-(5x-13)=0
We get rid of parentheses
3x^2/55-5x+13=0
We multiply all the terms by the denominator
3x^2-5x*55+13*55=0
We add all the numbers together, and all the variables
3x^2-5x*55+715=0
Wy multiply elements
3x^2-275x+715=0
a = 3; b = -275; c = +715;
Δ = b2-4ac
Δ = -2752-4·3·715
Δ = 67045
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-275)-\sqrt{67045}}{2*3}=\frac{275-\sqrt{67045}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-275)+\sqrt{67045}}{2*3}=\frac{275+\sqrt{67045}}{6} $
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