3x2=12x+351

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Solution for 3x2=12x+351 equation:



3x^2=12x+351
We move all terms to the left:
3x^2-(12x+351)=0
We get rid of parentheses
3x^2-12x-351=0
a = 3; b = -12; c = -351;
Δ = b2-4ac
Δ = -122-4·3·(-351)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-66}{2*3}=\frac{-54}{6} =-9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+66}{2*3}=\frac{78}{6} =13 $

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