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3x^2=12x+351
We move all terms to the left:
3x^2-(12x+351)=0
We get rid of parentheses
3x^2-12x-351=0
a = 3; b = -12; c = -351;
Δ = b2-4ac
Δ = -122-4·3·(-351)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-66}{2*3}=\frac{-54}{6} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+66}{2*3}=\frac{78}{6} =13 $
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