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3x^2=15x+7
We move all terms to the left:
3x^2-(15x+7)=0
We get rid of parentheses
3x^2-15x-7=0
a = 3; b = -15; c = -7;
Δ = b2-4ac
Δ = -152-4·3·(-7)
Δ = 309
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{309}}{2*3}=\frac{15-\sqrt{309}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{309}}{2*3}=\frac{15+\sqrt{309}}{6} $
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