3x2=17x+28

Solution for 3x2=17x+28 equation:

3x^2=17x+28

We move all terms to the left:

3x^2-(17x+28)=0

We get rid of parentheses

3x^2-17x-28=0

a = 3; b = -17; c = -28;
Δ = b2-4ac
Δ = -172-4·3·(-28)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-25}{2*3}=\frac{-8}{6}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+25}{2*3}=\frac{42}{6}
=7
$