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3x^2=21x-7=7
We move all terms to the left:
3x^2-(21x-7)=0
We get rid of parentheses
3x^2-21x+7=0
a = 3; b = -21; c = +7;
Δ = b2-4ac
Δ = -212-4·3·7
Δ = 357
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{357}}{2*3}=\frac{21-\sqrt{357}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{357}}{2*3}=\frac{21+\sqrt{357}}{6} $
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