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3x^2=25x+88
We move all terms to the left:
3x^2-(25x+88)=0
We get rid of parentheses
3x^2-25x-88=0
a = 3; b = -25; c = -88;
Δ = b2-4ac
Δ = -252-4·3·(-88)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-41}{2*3}=\frac{-16}{6} =-2+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+41}{2*3}=\frac{66}{6} =11 $
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