If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2=2x
We move all terms to the left:
3x^2-(2x)=0
a = 3; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·3·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*3}=\frac{0}{6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*3}=\frac{4}{6} =2/3 $
| -8+7m=56 | | 2-7y+4y=0 | | 4/5y-8=3 | | 5.8s=16700 | | 4m+16=44 | | 2x-5(x-2)=-8+4x-17 | | 7/6x-2/3=4/7x | | -8+7m=-56 | | F=9/5x40+32 | | x2+4=5x+4 | | 2-6n=-3+5(1-5n) | | 3+1k=8k-10 | | 4/5y-2=5 | | (6/5)(2/3)=x | | (1/2)x-6=(5/8)x | | 2(m-7)=3(m-2) | | 3m-14=7 | | 8z^2-14z+5=0 | | (6/5)/(2/3)=x | | 3^2-2×3+u=(3^3-3×8)(2)+u | | 2×+3y+12=0 | | (5.53)^t=14 | | 13v=21 | | 2/5+1/2x=1/5 | | 18m-3=12m | | -17-2x=6/x | | -3(a-4)-5a-12=-32 | | x^2+x=106.67 | | -6b+2(1-7b)=32 | | 1.3+0.5*9.44=x | | 4^x=5x^2 | | 20-r=8.43 |