3x2=43x+136

Solution for 3x2=43x+136 equation:

3x^2=43x+136

We move all terms to the left:

3x^2-(43x+136)=0

We get rid of parentheses

3x^2-43x-136=0

a = 3; b = -43; c = -136;
Δ = b2-4ac
Δ = -432-4·3·(-136)
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3481}=59$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-59}{2*3}=\frac{-16}{6}
=-2+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+59}{2*3}=\frac{102}{6}
=17
$