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3x^2=5-x2
We move all terms to the left:
3x^2-(5-x2)=0
We add all the numbers together, and all the variables
3x^2-(-1x^2+5)=0
We get rid of parentheses
3x^2+1x^2-5=0
We add all the numbers together, and all the variables
4x^2-5=0
a = 4; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·4·(-5)
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{5}}{2*4}=\frac{0-4\sqrt{5}}{8} =-\frac{4\sqrt{5}}{8} =-\frac{\sqrt{5}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{5}}{2*4}=\frac{0+4\sqrt{5}}{8} =\frac{4\sqrt{5}}{8} =\frac{\sqrt{5}}{2} $
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