3x2=5x+1

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Solution for 3x2=5x+1 equation:



3x^2=5x+1
We move all terms to the left:
3x^2-(5x+1)=0
We get rid of parentheses
3x^2-5x-1=0
a = 3; b = -5; c = -1;
Δ = b2-4ac
Δ = -52-4·3·(-1)
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{37}}{2*3}=\frac{5-\sqrt{37}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{37}}{2*3}=\frac{5+\sqrt{37}}{6} $

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