3x=(((-6x+4)*(-5))/10)+2

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Solution for 3x=(((-6x+4)*(-5))/10)+2 equation:



3x=(((-6x+4)(-5))/10)+2
We move all terms to the left:
3x-((((-6x+4)(-5))/10)+2)=0
We multiply parentheses ..
3x-((((+30x-20))/10)+2)=0
We multiply all the terms by the denominator
3x*10)+2)-((((+30x-20))=0
We add all the numbers together, and all the variables
3x*10)+2)-((((30x-20))=0
Wy multiply elements
30x^2=0
a = 30; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·30·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{60}=0$

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