3x=(-2x+1)/2

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Solution for 3x=(-2x+1)/2 equation:



3x=(-2x+1)/2
We move all terms to the left:
3x-((-2x+1)/2)=0
We multiply all the terms by the denominator
3x*2)-((-2x+1)=0
Wy multiply elements
6x^2=0
a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$

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