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3x=(-5(x)-4)/6
We move all terms to the left:
3x-((-5(x)-4)/6)=0
We multiply all the terms by the denominator
3x*6)-((-5x-4)=0
Wy multiply elements
18x^2=0
a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{36}=0$
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