3x=(2x+4(8x-1))

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Solution for 3x=(2x+4(8x-1)) equation: 



3x=(2x+4(8x-1))

We move all terms to the left:

3x-((2x+4(8x-1)))=0



We calculate terms in parentheses: -((2x+4(8x-1))), so:

(2x+4(8x-1))



We calculate terms in parentheses: +(2x+4(8x-1)), so:

2x+4(8x-1)

We multiply parentheses

2x+32x-4

We add all the numbers together, and all the variables

34x-4

Back to the equation:

+(34x-4)



We get rid of parentheses

34x-4

Back to the equation:

-(34x-4)



We get rid of parentheses

3x-34x+4=0

We add all the numbers together, and all the variables

-31x+4=0

We move all terms containing x to the left, all other terms to the right

-31x=-4

x=-4/-31

x=4/31

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