3x=(2x-3)=2x+9

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Solution for 3x=(2x-3)=2x+9 equation: 



3x=(2x-3)=2x+9

We move all terms to the left:

3x-((2x-3))=0



We calculate terms in parentheses: -((2x-3)), so:

(2x-3)

We get rid of parentheses

2x-3

Back to the equation:

-(2x-3)



We get rid of parentheses

3x-2x+3=0

We add all the numbers together, and all the variables

x+3=0

We move all terms containing x to the left, all other terms to the right

x=-3

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