3x=(x+1)(x+2)-3

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Solution for 3x=(x+1)(x+2)-3 equation: 


Simplifying
3x = (x + 1)(x + 2) + -3

Reorder the terms:
3x = (1 + x)(x + 2) + -3

Reorder the terms:
3x = (1 + x)(2 + x) + -3

Multiply (1 + x) * (2 + x)
3x = (1(2 + x) + x(2 + x)) + -3
3x = ((2 * 1 + x * 1) + x(2 + x)) + -3
3x = ((2 + 1x) + x(2 + x)) + -3
3x = (2 + 1x + (2 * x + x * x)) + -3
3x = (2 + 1x + (2x + x2)) + -3

Combine like terms: 1x + 2x = 3x
3x = (2 + 3x + x2) + -3

Reorder the terms:
3x = 2 + -3 + 3x + x2

Combine like terms: 2 + -3 = -1
3x = -1 + 3x + x2

Add '-3x' to each side of the equation.
3x + -3x = -1 + 3x + -3x + x2

Combine like terms: 3x + -3x = 0
0 = -1 + 3x + -3x + x2

Combine like terms: 3x + -3x = 0
0 = -1 + 0 + x2
0 = -1 + x2

Solving
0 = -1 + x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x2' to each side of the equation.
0 + -1x2 = -1 + x2 + -1x2
Remove the zero:
-1x2 = -1 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-1x2 = -1 + 0
-1x2 = -1

Divide each side by '-1'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}

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