3x=(x+1)5-41

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Solution for 3x=(x+1)5-41 equation: 



3x=(x+1)5-41

We move all terms to the left:

3x-((x+1)5-41)=0



We calculate terms in parentheses: -((x+1)5-41), so:

(x+1)5-41

We multiply parentheses

5x+5-41

We add all the numbers together, and all the variables

5x-36

Back to the equation:

-(5x-36)



We get rid of parentheses

3x-5x+36=0

We add all the numbers together, and all the variables

-2x+36=0

We move all terms containing x to the left, all other terms to the right

-2x=-36

x=-36/-2

x=+18

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