3x=(x+2)+108

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Solution for 3x=(x+2)+108 equation: 



3x=(x+2)+108

We move all terms to the left:

3x-((x+2)+108)=0



We calculate terms in parentheses: -((x+2)+108), so:

(x+2)+108

We get rid of parentheses

x+2+108

We add all the numbers together, and all the variables

x+110

Back to the equation:

-(x+110)



We get rid of parentheses

3x-x-110=0

We add all the numbers together, and all the variables

2x-110=0

We move all terms containing x to the left, all other terms to the right

2x=110

x=110/2

x=55

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