3x=(x/2)+15

Solution for 3x=(x/2)+15 equation:

3x=(x/2)+15

We move all terms to the left:

3x-((x/2)+15)=0

We add all the numbers together, and all the variables

3x-((+x/2)+15)=0

We multiply all the terms by the denominator


3x*2)+15)-((+x=0

We add all the numbers together, and all the variables

x+3x*2)+15)-((=0

Wy multiply elements

6x^2+x=0

a = 6; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·6·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*6}=\frac{-2}{12}
=-1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*6}=\frac{0}{12}
=0
$