3x=+8-2(1-x)=1

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Solution for 3x=+8-2(1-x)=1 equation:



3x=+8-2(1-x)=1
We move all terms to the left:
3x-(+8-2(1-x))=0
We add all the numbers together, and all the variables
3x-(+8-2(-1x+1))=0
We calculate terms in parentheses: -(+8-2(-1x+1)), so:
+8-2(-1x+1)
determiningTheFunctionDomain -2(-1x+1)+8
We multiply parentheses
2x-2+8
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
We get rid of parentheses
3x-2x-6=0
We add all the numbers together, and all the variables
x-6=0
We move all terms containing x to the left, all other terms to the right
x=6

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