3x=-4(8-4x)+4/4

Solution for 3x=-4(8-4x)+4/4 equation:

3x=-4(8-4x)+4/4

We move all terms to the left:

3x-(-4(8-4x)+4/4)=0

We add all the numbers together, and all the variables

3x-(-4(-4x+8)+4/4)=0

We multiply all the terms by the denominator


3x*4)-(-4(-4x+8)+4=0

We multiply parentheses

3x*4)-(+16x-32+4=0

Wy multiply elements

12x^2+16x-32+4=0

We add all the numbers together, and all the variables

12x^2+16x-28=0

a = 12; b = 16; c = -28;
Δ = b2-4ac
Δ = 162-4·12·(-28)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-40}{2*12}=\frac{-56}{24}
=-2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+40}{2*12}=\frac{24}{24}
=1
$