3x=12+2y;-6/5x+y=-9/5

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for example:
2x+y=8
x+3y=14

Solution for 3x=12+2y;-6/5x+y=-9/5 system of equations: 


  • /| 3*x-(2*y)-12 = 0| (-6/5)*x+y-(-9/5) = 0
  • We try to solve the equation: 3*x-(2*y)-12 = 0
  • 3*x-2*y-12 = 0 // - 3*x-12
  • -2*y = -(3*x-12) // : -2
  • y = (-(3*x-12))/(-2)
  • y = (12-(3*x))/(-2)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| (12-(3*x))/(-2)+(-6/5)*x-(-9/5) = 0| y = (12-(3*x))/(-2)
  • (12-3*x)/(-2)+(-6*x)/5+9/5 = 0
  • 3/10*x-6+9/5 = 0
  • 3/10*x-21/5 = 0
  • 3/10*x-21/5 = 0 // + 21/5
  • 3/10*x = 21/5 // : 3/10
  • x = 21/5/3/10
  • x = 14
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (12-(3*x))/(-2): 
  • y = (12-(3*14))/(-2)
  • y = (12-42)/(-2)
  • y = -30/(-2)
  • y = 15
  • We get a system of equations:
  • /| y = 15| x = 14

 

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