3x=16+(5x+12)

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Solution for 3x=16+(5x+12) equation: 



3x=16+(5x+12)

We move all terms to the left:

3x-(16+(5x+12))=0



We calculate terms in parentheses: -(16+(5x+12)), so:

16+(5x+12)

determiningTheFunctionDomain
(5x+12)+16

We get rid of parentheses

5x+12+16

We add all the numbers together, and all the variables

5x+28

Back to the equation:

-(5x+28)



We get rid of parentheses

3x-5x-28=0

We add all the numbers together, and all the variables

-2x-28=0

We move all terms containing x to the left, all other terms to the right

-2x=28

x=28/-2

x=-14

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