3x=2(x+1)-x-2

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Solution for 3x=2(x+1)-x-2 equation:



3x=2(x+1)-x-2
We move all terms to the left:
3x-(2(x+1)-x-2)=0
We calculate terms in parentheses: -(2(x+1)-x-2), so:
2(x+1)-x-2
We add all the numbers together, and all the variables
-1x+2(x+1)-2
We multiply parentheses
-1x+2x+2-2
We add all the numbers together, and all the variables
x
Back to the equation:
-(x)
We add all the numbers together, and all the variables
2x=0
x=0/2
x=0

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