3x=2(x/4)+2(x+3)

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Solution for 3x=2(x/4)+2(x+3) equation: 



3x=2(x/4)+2(x+3)

We move all terms to the left:

3x-(2(x/4)+2(x+3))=0



Domain of the equation: 4)+2(x+3))!=0

x∈R



We add all the numbers together, and all the variables

3x-(2(+x/4)+2(x+3))=0

We multiply all the terms by the denominator


3x*4)+2(x+x+3))-(2(=0

We add all the numbers together, and all the variables

3x*4)+2(2x+3))-(2(=0

We add all the numbers together, and all the variables

3x*4)+2(2x=0

Wy multiply elements

12x^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$

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