3x=2/3+(3x-2)

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Solution for 3x=2/3+(3x-2) equation: 



3x=2/3+(3x-2)

We move all terms to the left:

3x-(2/3+(3x-2))=0



Domain of the equation: 3+(3x-2))!=0

We move all terms containing x to the left, all other terms to the right

(3x-2))!=-3

x∈R



We multiply all the terms by the denominator


3x*3+(3x-2))-(2=0

Wy multiply elements

9x+(3x-2))-(2=0

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