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3x=225/5x
We move all terms to the left:
3x-(225/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x-(+225/5x)=0
We get rid of parentheses
3x-225/5x=0
We multiply all the terms by the denominator
3x*5x-225=0
Wy multiply elements
15x^2-225=0
a = 15; b = 0; c = -225;
Δ = b2-4ac
Δ = 02-4·15·(-225)
Δ = 13500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13500}=\sqrt{900*15}=\sqrt{900}*\sqrt{15}=30\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30\sqrt{15}}{2*15}=\frac{0-30\sqrt{15}}{30} =-\frac{30\sqrt{15}}{30} =-\sqrt{15} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30\sqrt{15}}{2*15}=\frac{0+30\sqrt{15}}{30} =\frac{30\sqrt{15}}{30} =\sqrt{15} $
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