3x=23(x+4)/8

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Solution for 3x=23(x+4)/8 equation: 



3x=23(x+4)/8

We move all terms to the left:

3x-(23(x+4)/8)=0

We multiply all the terms by the denominator


3x*8)-(23(x+4)=0

Wy multiply elements

24x^2=0

a = 24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·24·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{48}=0$

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