3x=2x(x-5)

Solution for 3x=2x(x-5) equation:

3x=2x(x-5)

We move all terms to the left:

3x-(2x(x-5))=0


We calculate terms in parentheses: -(2x(x-5)), so:

2x(x-5)

We multiply parentheses

2x^2-10x

Back to the equation:

-(2x^2-10x)


We get rid of parentheses

-2x^2+3x+10x=0

We add all the numbers together, and all the variables

-2x^2+13x=0

a = -2; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·(-2)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*-2}=\frac{-26}{-4}
=6+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*-2}=\frac{0}{-4}
=0
$