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3x=2x/3x
We move all terms to the left:
3x-(2x/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x-(+2x/3x)=0
We get rid of parentheses
3x-2x/3x=0
We multiply all the terms by the denominator
3x*3x-2x=0
We add all the numbers together, and all the variables
-2x+3x*3x=0
Wy multiply elements
9x^2-2x=0
a = 9; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·9·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*9}=\frac{0}{18} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*9}=\frac{4}{18} =2/9 $
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