3x=3(x-4)+12

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Solution for 3x=3(x-4)+12 equation: 



3x=3(x-4)+12

We move all terms to the left:

3x-(3(x-4)+12)=0



We calculate terms in parentheses: -(3(x-4)+12), so:

3(x-4)+12

We multiply parentheses

3x-12+12

We add all the numbers together, and all the variables

3x

Back to the equation:

-(3x)



We add all the numbers together, and all the variables

=0

x=0/1

x=0

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