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3x=3/5x
We move all terms to the left:
3x-(3/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x-(+3/5x)=0
We get rid of parentheses
3x-3/5x=0
We multiply all the terms by the denominator
3x*5x-3=0
Wy multiply elements
15x^2-3=0
a = 15; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·15·(-3)
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{5}}{2*15}=\frac{0-6\sqrt{5}}{30} =-\frac{6\sqrt{5}}{30} =-\frac{\sqrt{5}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{5}}{2*15}=\frac{0+6\sqrt{5}}{30} =\frac{6\sqrt{5}}{30} =\frac{\sqrt{5}}{5} $
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