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3x=324/x
We move all terms to the left:
3x-(324/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x-(+324/x)=0
We get rid of parentheses
3x-324/x=0
We multiply all the terms by the denominator
3x*x-324=0
Wy multiply elements
3x^2-324=0
a = 3; b = 0; c = -324;
Δ = b2-4ac
Δ = 02-4·3·(-324)
Δ = 3888
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3888}=\sqrt{1296*3}=\sqrt{1296}*\sqrt{3}=36\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36\sqrt{3}}{2*3}=\frac{0-36\sqrt{3}}{6} =-\frac{36\sqrt{3}}{6} =-6\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36\sqrt{3}}{2*3}=\frac{0+36\sqrt{3}}{6} =\frac{36\sqrt{3}}{6} =6\sqrt{3} $
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