3x=3x2+2x-6

Solution for 3x=3x2+2x-6 equation:

3x=3x^2+2x-6

We move all terms to the left:

3x-(3x^2+2x-6)=0

We get rid of parentheses

-3x^2+3x-2x+6=0

We add all the numbers together, and all the variables

-3x^2+x+6=0

a = -3; b = 1; c = +6;
Δ = b2-4ac
Δ = 12-4·(-3)·6
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{73}}{2*-3}=\frac{-1-\sqrt{73}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{73}}{2*-3}=\frac{-1+\sqrt{73}}{-6}
$