3x=4+(-8x/16)

Solution for 3x=4+(-8x/16) equation:

3x=4+(-8x/16)

We move all terms to the left:

3x-(4+(-8x/16))=0

We multiply all the terms by the denominator


3x*16))-(4+(-8x=0

We add all the numbers together, and all the variables

-8x+3x*16))-(4+(=0

Wy multiply elements

48x^2-8x=0

a = 48; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·48·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*48}=\frac{0}{96}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*48}=\frac{16}{96}
=1/6
$