3x=40+(x+15)

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Solution for 3x=40+(x+15) equation: 



3x=40+(x+15)

We move all terms to the left:

3x-(40+(x+15))=0



We calculate terms in parentheses: -(40+(x+15)), so:

40+(x+15)

determiningTheFunctionDomain
(x+15)+40

We get rid of parentheses

x+15+40

We add all the numbers together, and all the variables

x+55

Back to the equation:

-(x+55)



We get rid of parentheses

3x-x-55=0

We add all the numbers together, and all the variables

2x-55=0

We move all terms containing x to the left, all other terms to the right

2x=55

x=55/2

x=27+1/2

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