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3x=50+1/2x
We move all terms to the left:
3x-(50+1/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x-(1/2x+50)=0
We get rid of parentheses
3x-1/2x-50=0
We multiply all the terms by the denominator
3x*2x-50*2x-1=0
Wy multiply elements
6x^2-100x-1=0
a = 6; b = -100; c = -1;
Δ = b2-4ac
Δ = -1002-4·6·(-1)
Δ = 10024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10024}=\sqrt{4*2506}=\sqrt{4}*\sqrt{2506}=2\sqrt{2506}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-2\sqrt{2506}}{2*6}=\frac{100-2\sqrt{2506}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+2\sqrt{2506}}{2*6}=\frac{100+2\sqrt{2506}}{12} $
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