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3x=51/2x
We move all terms to the left:
3x-(51/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x-(+51/2x)=0
We get rid of parentheses
3x-51/2x=0
We multiply all the terms by the denominator
3x*2x-51=0
Wy multiply elements
6x^2-51=0
a = 6; b = 0; c = -51;
Δ = b2-4ac
Δ = 02-4·6·(-51)
Δ = 1224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1224}=\sqrt{36*34}=\sqrt{36}*\sqrt{34}=6\sqrt{34}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{34}}{2*6}=\frac{0-6\sqrt{34}}{12} =-\frac{6\sqrt{34}}{12} =-\frac{\sqrt{34}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{34}}{2*6}=\frac{0+6\sqrt{34}}{12} =\frac{6\sqrt{34}}{12} =\frac{\sqrt{34}}{2} $
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