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3x=54/3x+15=21
We move all terms to the left:
3x-(54/3x+15)=0
Domain of the equation: 3x+15)!=0We get rid of parentheses
x∈R
3x-54/3x-15=0
We multiply all the terms by the denominator
3x*3x-15*3x-54=0
Wy multiply elements
9x^2-45x-54=0
a = 9; b = -45; c = -54;
Δ = b2-4ac
Δ = -452-4·9·(-54)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-63}{2*9}=\frac{-18}{18} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+63}{2*9}=\frac{108}{18} =6 $
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